6(2a-3)+10=5(a-3)

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Solution for 6(2a-3)+10=5(a-3) equation: 



6(2a-3)+10=5(a-3)

We move all terms to the left:

6(2a-3)+10-(5(a-3))=0

We multiply parentheses

12a-(5(a-3))-18+10=0



We calculate terms in parentheses: -(5(a-3)), so:

5(a-3)

We multiply parentheses

5a-15

Back to the equation:

-(5a-15)



We add all the numbers together, and all the variables

12a-(5a-15)-8=0

We get rid of parentheses

12a-5a+15-8=0

We add all the numbers together, and all the variables

7a+7=0

We move all terms containing a to the left, all other terms to the right

7a=-7

a=-7/7

a=-1

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