9(t-4)+3t=6(2t+2)-9

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Solution for 9(t-4)+3t=6(2t+2)-9 equation: 



9(t-4)+3t=6(2t+2)-9

We move all terms to the left:

9(t-4)+3t-(6(2t+2)-9)=0

We add all the numbers together, and all the variables

3t+9(t-4)-(6(2t+2)-9)=0

We multiply parentheses

3t+9t-(6(2t+2)-9)-36=0



We calculate terms in parentheses: -(6(2t+2)-9), so:

6(2t+2)-9

We multiply parentheses

12t+12-9

We add all the numbers together, and all the variables

12t+3

Back to the equation:

-(12t+3)



We add all the numbers together, and all the variables

12t-(12t+3)-36=0

We get rid of parentheses

12t-12t-3-36=0

We add all the numbers together, and all the variables

-39!=0

There is no solution for this equation

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