12=-8(1+x)+2(1+x)

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Solution for 12=-8(1+x)+2(1+x) equation: 



12=-8(1+x)+2(1+x)

We move all terms to the left:

12-(-8(1+x)+2(1+x))=0

We add all the numbers together, and all the variables

-(-8(x+1)+2(x+1))+12=0



We calculate terms in parentheses: -(-8(x+1)+2(x+1)), so:

-8(x+1)+2(x+1)

We multiply parentheses

-8x+2x-8+2

We add all the numbers together, and all the variables

-6x-6

Back to the equation:

-(-6x-6)



We get rid of parentheses

6x+6+12=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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