9(t+12)=3(t-2)

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Solution for 9(t+12)=3(t-2) equation: 



9(t+12)=3(t-2)

We move all terms to the left:

9(t+12)-(3(t-2))=0

We multiply parentheses

9t-(3(t-2))+108=0



We calculate terms in parentheses: -(3(t-2)), so:

3(t-2)

We multiply parentheses

3t-6

Back to the equation:

-(3t-6)



We get rid of parentheses

9t-3t+6+108=0

We add all the numbers together, and all the variables

6t+114=0

We move all terms containing t to the left, all other terms to the right

6t=-114

t=-114/6

t=-19

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