-3(v+2)=v-1+2(4v+2)

Solution for -3(v+2)=v-1+2(4v+2) equation:

-3(v+2)=v-1+2(4v+2)

We move all terms to the left:

-3(v+2)-(v-1+2(4v+2))=0

We multiply parentheses

-3v-(v-1+2(4v+2))-6=0


We calculate terms in parentheses: -(v-1+2(4v+2)), so:

v-1+2(4v+2)

determiningTheFunctionDomain
v+2(4v+2)-1

We multiply parentheses

v+8v+4-1

We add all the numbers together, and all the variables

9v+3

Back to the equation:

-(9v+3)


We get rid of parentheses

-3v-9v-3-6=0

We add all the numbers together, and all the variables

-12v-9=0

We move all terms containing v to the left, all other terms to the right

-12v=9

v=9/-12

v=-3/4