9(n+1)=3(5+n)

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Solution for 9(n+1)=3(5+n) equation: 



9(n+1)=3(5+n)

We move all terms to the left:

9(n+1)-(3(5+n))=0

We add all the numbers together, and all the variables

9(n+1)-(3(n+5))=0

We multiply parentheses

9n-(3(n+5))+9=0



We calculate terms in parentheses: -(3(n+5)), so:

3(n+5)

We multiply parentheses

3n+15

Back to the equation:

-(3n+15)



We get rid of parentheses

9n-3n-15+9=0

We add all the numbers together, and all the variables

6n-6=0

We move all terms containing n to the left, all other terms to the right

6n=6

n=6/6

n=1

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