5x+2(x-3)=-2(x-1)7x-6=-2x-27x-6=-2x+27x-3=-2x-1

Solution for 5x+2(x-3)=-2(x-1)7x-6=-2x-27x-6=-2x+27x-3=-2x-1 equation:

5x+2(x-3)=-2(x-1)7x-6=-2x-27x-6=-2x+27x-3=-2x-1

We move all terms to the left:

5x+2(x-3)-(-2(x-1)7x-6)=0

We multiply parentheses

5x+2x-(-2(x-1)7x-6)-6=0


We calculate terms in parentheses: -(-2(x-1)7x-6), so:

-2(x-1)7x-6

We multiply parentheses

-14x^2+14x-6

Back to the equation:

-(-14x^2+14x-6)


We add all the numbers together, and all the variables

-(-14x^2+14x-6)+7x-6=0

We get rid of parentheses

14x^2-14x+7x+6-6=0

We add all the numbers together, and all the variables

14x^2-7x=0

a = 14; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·14·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*14}=\frac{0}{28}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*14}=\frac{14}{28}
=1/2
$