9(k-4)-7k=32-2(k+8)*

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Solution for 9(k-4)-7k=32-2(k+8)* equation:



9(k-4)-7k=32-2(k+8)*
We move all terms to the left:
9(k-4)-7k-(32-2(k+8)*)=0
We add all the numbers together, and all the variables
-7k+9(k-4)-(32-2(k+8)*)=0
We multiply parentheses
-7k+9k-(32-2(k+8)*)-36=0
We calculate terms in parentheses: -(32-2(k+8)*), so:
32-2(k+8)*
determiningTheFunctionDomain -2(k+8)*+32
We multiply parentheses
-2k-16+32
We add all the numbers together, and all the variables
-2k+16
Back to the equation:
-(-2k+16)
We add all the numbers together, and all the variables
2k-(-2k+16)-36=0
We get rid of parentheses
2k+2k-16-36=0
We add all the numbers together, and all the variables
4k-52=0
We move all terms containing k to the left, all other terms to the right
4k=52
k=52/4
k=13

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