2(x+5)+2x=20+3(2x-4)

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Solution for 2(x+5)+2x=20+3(2x-4) equation: 



2(x+5)+2x=20+3(2x-4)

We move all terms to the left:

2(x+5)+2x-(20+3(2x-4))=0

We add all the numbers together, and all the variables

2x+2(x+5)-(20+3(2x-4))=0

We multiply parentheses

2x+2x-(20+3(2x-4))+10=0



We calculate terms in parentheses: -(20+3(2x-4)), so:

20+3(2x-4)

determiningTheFunctionDomain
3(2x-4)+20

We multiply parentheses

6x-12+20

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

4x-(6x+8)+10=0

We get rid of parentheses

4x-6x-8+10=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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