9(k+5)+10=-6(1-6k)

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Solution for 9(k+5)+10=-6(1-6k) equation: 



9(k+5)+10=-6(1-6k)

We move all terms to the left:

9(k+5)+10-(-6(1-6k))=0

We add all the numbers together, and all the variables

9(k+5)-(-6(-6k+1))+10=0

We multiply parentheses

9k-(-6(-6k+1))+45+10=0



We calculate terms in parentheses: -(-6(-6k+1)), so:

-6(-6k+1)

We multiply parentheses

36k-6

Back to the equation:

-(36k-6)



We add all the numbers together, and all the variables

9k-(36k-6)+55=0

We get rid of parentheses

9k-36k+6+55=0

We add all the numbers together, and all the variables

-27k+61=0

We move all terms containing k to the left, all other terms to the right

-27k=-61

k=-61/-27

k=2+7/27

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