-3(-8-4x)=40-21(4+3x)

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Solution for -3(-8-4x)=40-21(4+3x) equation: 



-3(-8-4x)=40-21(4+3x)

We move all terms to the left:

-3(-8-4x)-(40-21(4+3x))=0

We add all the numbers together, and all the variables

-3(-4x-8)-(40-21(3x+4))=0

We multiply parentheses

12x-(40-21(3x+4))+24=0



We calculate terms in parentheses: -(40-21(3x+4)), so:

40-21(3x+4)

determiningTheFunctionDomain
-21(3x+4)+40

We multiply parentheses

-63x-84+40

We add all the numbers together, and all the variables

-63x-44

Back to the equation:

-(-63x-44)



We get rid of parentheses

12x+63x+44+24=0

We add all the numbers together, and all the variables

75x+68=0

We move all terms containing x to the left, all other terms to the right

75x=-68

x=-68/75

x=-68/75

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