8u-2+2(4u+1)=-2(u+8)

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Solution for 8u-2+2(4u+1)=-2(u+8) equation: 



8u-2+2(4u+1)=-2(u+8)

We move all terms to the left:

8u-2+2(4u+1)-(-2(u+8))=0

We multiply parentheses

8u+8u-(-2(u+8))+2-2=0



We calculate terms in parentheses: -(-2(u+8)), so:

-2(u+8)

We multiply parentheses

-2u-16

Back to the equation:

-(-2u-16)



We add all the numbers together, and all the variables

16u-(-2u-16)=0

We get rid of parentheses

16u+2u+16=0

We add all the numbers together, and all the variables

18u+16=0

We move all terms containing u to the left, all other terms to the right

18u=-16

u=-16/18

u=-8/9

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