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3(5-3x)=2(x-4)-21
We move all terms to the left:
3(5-3x)-(2(x-4)-21)=0
We add all the numbers together, and all the variables
3(-3x+5)-(2(x-4)-21)=0
We multiply parentheses
-9x-(2(x-4)-21)+15=0
We calculate terms in parentheses: -(2(x-4)-21), so:We get rid of parentheses
2(x-4)-21
We multiply parentheses
2x-8-21
We add all the numbers together, and all the variables
2x-29
Back to the equation:
-(2x-29)
-9x-2x+29+15=0
We add all the numbers together, and all the variables
-11x+44=0
We move all terms containing x to the left, all other terms to the right
-11x=-44
x=-44/-11
x=+4
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