9(e+3)-6=3(e-4)-15

Solution for 9(e+3)-6=3(e-4)-15 equation:

9(e+3)-6=3(e-4)-15

We move all terms to the left:

9(e+3)-6-(3(e-4)-15)=0

We multiply parentheses

9e-(3(e-4)-15)+27-6=0


We calculate terms in parentheses: -(3(e-4)-15), so:

3(e-4)-15

We multiply parentheses

3e-12-15

We add all the numbers together, and all the variables

3e-27

Back to the equation:

-(3e-27)


We add all the numbers together, and all the variables

9e-(3e-27)+21=0

We get rid of parentheses

9e-3e+27+21=0

We add all the numbers together, and all the variables

6e+48=0

We move all terms containing e to the left, all other terms to the right

6e=-48

e=-48/6

e=-8