9(k-2)+1=2(k+2)+7

Solution for 9(k-2)+1=2(k+2)+7 equation:

9(k-2)+1=2(k+2)+7

We move all terms to the left:

9(k-2)+1-(2(k+2)+7)=0

We multiply parentheses

9k-(2(k+2)+7)-18+1=0


We calculate terms in parentheses: -(2(k+2)+7), so:

2(k+2)+7

We multiply parentheses

2k+4+7

We add all the numbers together, and all the variables

2k+11

Back to the equation:

-(2k+11)


We add all the numbers together, and all the variables

9k-(2k+11)-17=0

We get rid of parentheses

9k-2k-11-17=0

We add all the numbers together, and all the variables

7k-28=0

We move all terms containing k to the left, all other terms to the right

7k=28

k=28/7

k=4