9(c-7)+3=3c+3

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Solution for 9(c-7)+3=3c+3 equation: 



9(c-7)+3=3c+3

We move all terms to the left:

9(c-7)+3-(3c+3)=0

We multiply parentheses

9c-(3c+3)-63+3=0

We get rid of parentheses

9c-3c-3-63+3=0

We add all the numbers together, and all the variables

6c-63=0

We move all terms containing c to the left, all other terms to the right

6c=63

c=63/6

c=10+1/2

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