3(4c+9)=8c+1-(2c-11)

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Solution for 3(4c+9)=8c+1-(2c-11) equation: 



3(4c+9)=8c+1-(2c-11)

We move all terms to the left:

3(4c+9)-(8c+1-(2c-11))=0

We multiply parentheses

12c-(8c+1-(2c-11))+27=0



We calculate terms in parentheses: -(8c+1-(2c-11)), so:

8c+1-(2c-11)

determiningTheFunctionDomain
8c-(2c-11)+1

We get rid of parentheses

8c-2c+11+1

We add all the numbers together, and all the variables

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

12c-6c-12+27=0

We add all the numbers together, and all the variables

6c+15=0

We move all terms containing c to the left, all other terms to the right

6c=-15

c=-15/6

c=-2+1/2

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