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12x=168/3+5x
We move all terms to the left:
12x-(168/3+5x)=0
Domain of the equation: 3+5x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x)!=-3
x!=-3/1
x!=-3
x∈R
12x-(5x+56)=0
We get rid of parentheses
12x-5x-56=0
We add all the numbers together, and all the variables
7x-56=0
We move all terms containing x to the left, all other terms to the right
7x=56
x=56/7
x=8
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