9(b-3)=5(3b-5)

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Solution for 9(b-3)=5(3b-5) equation: 



9(b-3)=5(3b-5)

We move all terms to the left:

9(b-3)-(5(3b-5))=0

We multiply parentheses

9b-(5(3b-5))-27=0



We calculate terms in parentheses: -(5(3b-5)), so:

5(3b-5)

We multiply parentheses

15b-25

Back to the equation:

-(15b-25)



We get rid of parentheses

9b-15b+25-27=0

We add all the numbers together, and all the variables

-6b-2=0

We move all terms containing b to the left, all other terms to the right

-6b=2

b=2/-6

b=-1/3

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