z/5=(z+2)/7

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Solution for z/5=(z+2)/7 equation: 



z/5=(z+2)/7

We move all terms to the left:

z/5-((z+2)/7)=0

We calculate fractions


7z^2/()+(-((z+2)*5)/()=0



We calculate terms in parentheses: +(-((z+2)*5)/(), so:

-((z+2)*5)/(

We multiply all the terms by the denominator


-((z+2)*5)



We calculate terms in parentheses: -((z+2)*5), so:

(z+2)*5

We multiply parentheses

5z+10

Back to the equation:

-(5z+10)



We get rid of parentheses

-5z-10

Back to the equation:

+(-5z-10)



We get rid of parentheses

7z^2/()-5z-10=0

We multiply all the terms by the denominator


7z^2-5z*()-10*()=0

We add all the numbers together, and all the variables

7z^2-5z*()=0

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