9(8x+3)(x-8)=0

Solution for 9(8x+3)(x-8)=0 equation:

9(8x+3)(x-8)=0

We multiply parentheses ..

9(+8x^2-64x+3x-24)=0

We multiply parentheses

72x^2-576x+27x-216=0

We add all the numbers together, and all the variables

72x^2-549x-216=0

a = 72; b = -549; c = -216;
Δ = b2-4ac
Δ = -5492-4·72·(-216)
Δ = 363609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{363609}=603$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-549)-603}{2*72}=\frac{-54}{144}
=-3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-549)+603}{2*72}=\frac{1152}{144}
=8
$