3(y-1)+2(y+3)=27-3y

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Solution for 3(y-1)+2(y+3)=27-3y equation: 



3(y-1)+2(y+3)=27-3y

We move all terms to the left:

3(y-1)+2(y+3)-(27-3y)=0

We add all the numbers together, and all the variables

3(y-1)+2(y+3)-(-3y+27)=0

We multiply parentheses

3y+2y-(-3y+27)-3+6=0

We get rid of parentheses

3y+2y+3y-27-3+6=0

We add all the numbers together, and all the variables

8y-24=0

We move all terms containing y to the left, all other terms to the right

8y=24

y=24/8

y=3

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