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6x-2(x-5)=3(x-2)
We move all terms to the left:
6x-2(x-5)-(3(x-2))=0
We multiply parentheses
6x-2x-(3(x-2))+10=0
We calculate terms in parentheses: -(3(x-2)), so:We add all the numbers together, and all the variables
3(x-2)
We multiply parentheses
3x-6
Back to the equation:
-(3x-6)
4x-(3x-6)+10=0
We get rid of parentheses
4x-3x+6+10=0
We add all the numbers together, and all the variables
x+16=0
We move all terms containing x to the left, all other terms to the right
x=-16
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