4(n+5)=28+2n

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Solution for 4(n+5)=28+2n equation: 



4(n+5)=28+2n

We move all terms to the left:

4(n+5)-(28+2n)=0

We add all the numbers together, and all the variables

4(n+5)-(2n+28)=0

We multiply parentheses

4n-(2n+28)+20=0

We get rid of parentheses

4n-2n-28+20=0

We add all the numbers together, and all the variables

2n-8=0

We move all terms containing n to the left, all other terms to the right

2n=8

n=8/2

n=4

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