9(6x+7)+4(20x-12)+78=15(9x+13)-7(6x-3)

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Solution for 9(6x+7)+4(20x-12)+78=15(9x+13)-7(6x-3) equation: 



9(6x+7)+4(20x-12)+78=15(9x+13)-7(6x-3)

We move all terms to the left:

9(6x+7)+4(20x-12)+78-(15(9x+13)-7(6x-3))=0

We multiply parentheses

54x+80x-(15(9x+13)-7(6x-3))+63-48+78=0



We calculate terms in parentheses: -(15(9x+13)-7(6x-3)), so:

15(9x+13)-7(6x-3)

We multiply parentheses

135x-42x+195+21

We add all the numbers together, and all the variables

93x+216

Back to the equation:

-(93x+216)



We add all the numbers together, and all the variables

134x-(93x+216)+93=0

We get rid of parentheses

134x-93x-216+93=0

We add all the numbers together, and all the variables

41x-123=0

We move all terms containing x to the left, all other terms to the right

41x=123

x=123/41

x=3

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