5(2x+3)=4x+27

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Solution for 5(2x+3)=4x+27 equation: 



5(2x+3)=4x+27

We move all terms to the left:

5(2x+3)-(4x+27)=0

We multiply parentheses

10x-(4x+27)+15=0

We get rid of parentheses

10x-4x-27+15=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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