9(4y-3y+7)=4(9y-7+5)/3

Solution for 9(4y-3y+7)=4(9y-7+5)/3 equation:

9(4y-3y+7)=4(9y-7+5)/3

We move all terms to the left:

9(4y-3y+7)-(4(9y-7+5)/3)=0

We add all the numbers together, and all the variables

9(y+7)-(4(9y-2)/3)=0

We multiply parentheses

9y-(4(9y-2)/3)+63=0

We multiply all the terms by the denominator


9y*3)-(4(9y-2)+63*3)=0

We add all the numbers together, and all the variables

9y*3)-(4(9y-2)=0

Wy multiply elements

27y^2=0

a = 27; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·27·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{54}=0$