3n(6+3)+5n=4+3(2n+3)

Solution for 3n(6+3)+5n=4+3(2n+3) equation:

3n(6+3)+5n=4+3(2n+3)

We move all terms to the left:

3n(6+3)+5n-(4+3(2n+3))=0

We add all the numbers together, and all the variables

3n9+5n-(4+3(2n+3))=0

We add all the numbers together, and all the variables

3n^9+5n-(4+3(2n+3))=0


We calculate terms in parentheses: -(4+3(2n+3)), so:

4+3(2n+3)

determiningTheFunctionDomain
3(2n+3)+4

We multiply parentheses

6n+9+4

We add all the numbers together, and all the variables

6n+13

Back to the equation:

-(6n+13)


We do not support enpression: n^9