9(4x-5)=6(3-x)

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Solution for 9(4x-5)=6(3-x) equation: 



9(4x-5)=6(3-x)

We move all terms to the left:

9(4x-5)-(6(3-x))=0

We add all the numbers together, and all the variables

9(4x-5)-(6(-1x+3))=0

We multiply parentheses

36x-(6(-1x+3))-45=0



We calculate terms in parentheses: -(6(-1x+3)), so:

6(-1x+3)

We multiply parentheses

-6x+18

Back to the equation:

-(-6x+18)



We get rid of parentheses

36x+6x-18-45=0

We add all the numbers together, and all the variables

42x-63=0

We move all terms containing x to the left, all other terms to the right

42x=63

x=63/42

x=1+1/2

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