12=2-3(2y+6)

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Solution for 12=2-3(2y+6) equation: 



12=2-3(2y+6)

We move all terms to the left:

12-(2-3(2y+6))=0



We calculate terms in parentheses: -(2-3(2y+6)), so:

2-3(2y+6)

determiningTheFunctionDomain
-3(2y+6)+2

We multiply parentheses

-6y-18+2

We add all the numbers together, and all the variables

-6y-16

Back to the equation:

-(-6y-16)



We get rid of parentheses

6y+16+12=0

We add all the numbers together, and all the variables

6y+28=0

We move all terms containing y to the left, all other terms to the right

6y=-28

y=-28/6

y=-4+2/3

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