9(4d-1)=2(9d+3)

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Solution for 9(4d-1)=2(9d+3) equation: 



9(4d-1)=2(9d+3)

We move all terms to the left:

9(4d-1)-(2(9d+3))=0

We multiply parentheses

36d-(2(9d+3))-9=0



We calculate terms in parentheses: -(2(9d+3)), so:

2(9d+3)

We multiply parentheses

18d+6

Back to the equation:

-(18d+6)



We get rid of parentheses

36d-18d-6-9=0

We add all the numbers together, and all the variables

18d-15=0

We move all terms containing d to the left, all other terms to the right

18d=15

d=15/18

d=5/6

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