1000(7x+-10)=50(396+100x)

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Solution for 1000(7x+-10)=50(396+100x) equation: 



1000(7x+-10)=50(396+100x)

We move all terms to the left:

1000(7x+-10)-(50(396+100x))=0

We add all the numbers together, and all the variables

1000(7x-10)-(50(100x+396))=0

We multiply parentheses

7000x-(50(100x+396))-10000=0



We calculate terms in parentheses: -(50(100x+396)), so:

50(100x+396)

We multiply parentheses

5000x+19800

Back to the equation:

-(5000x+19800)



We get rid of parentheses

7000x-5000x-19800-10000=0

We add all the numbers together, and all the variables

2000x-29800=0

We move all terms containing x to the left, all other terms to the right

2000x=29800

x=29800/2000

x=14+9/10

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