9(3y+5)=4(4y-3)

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Solution for 9(3y+5)=4(4y-3) equation: 



9(3y+5)=4(4y-3)

We move all terms to the left:

9(3y+5)-(4(4y-3))=0

We multiply parentheses

27y-(4(4y-3))+45=0



We calculate terms in parentheses: -(4(4y-3)), so:

4(4y-3)

We multiply parentheses

16y-12

Back to the equation:

-(16y-12)



We get rid of parentheses

27y-16y+12+45=0

We add all the numbers together, and all the variables

11y+57=0

We move all terms containing y to the left, all other terms to the right

11y=-57

y=-57/11

y=-5+2/11

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