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5(2x+4)+10=2(10-x)
We move all terms to the left:
5(2x+4)+10-(2(10-x))=0
We add all the numbers together, and all the variables
5(2x+4)-(2(-1x+10))+10=0
We multiply parentheses
10x-(2(-1x+10))+20+10=0
We calculate terms in parentheses: -(2(-1x+10)), so:We add all the numbers together, and all the variables
2(-1x+10)
We multiply parentheses
-2x+20
Back to the equation:
-(-2x+20)
10x-(-2x+20)+30=0
We get rid of parentheses
10x+2x-20+30=0
We add all the numbers together, and all the variables
12x+10=0
We move all terms containing x to the left, all other terms to the right
12x=-10
x=-10/12
x=-5/6
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