9(3x-1)3=3x(3x-1)

Solution for 9(3x-1)3=3x(3x-1) equation:

9(3x-1)3=3x(3x-1)

We move all terms to the left:

9(3x-1)3-(3x(3x-1))=0

We multiply parentheses

81x-(3x(3x-1))-27=0


We calculate terms in parentheses: -(3x(3x-1)), so:

3x(3x-1)

We multiply parentheses

9x^2-3x

Back to the equation:

-(9x^2-3x)


We get rid of parentheses

-9x^2+81x+3x-27=0

We add all the numbers together, and all the variables

-9x^2+84x-27=0

a = -9; b = 84; c = -27;
Δ = b2-4ac
Δ = 842-4·(-9)·(-27)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-78}{2*-9}=\frac{-162}{-18}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+78}{2*-9}=\frac{-6}{-18}
=1/3
$