8-7/10c=31/6c

Solution for 8-7/10c=31/6c equation:

8-7/10c=31/6c

We move all terms to the left:

8-7/10c-(31/6c)=0


Domain of the equation: 10c!=0

c!=0/10

c!=0

c∈R



Domain of the equation: 6c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

-7/10c-(+31/6c)+8=0

We get rid of parentheses

-7/10c-31/6c+8=0

We calculate fractions


(-42c)/60c^2+(-310c)/60c^2+8=0

We multiply all the terms by the denominator


(-42c)+(-310c)+8*60c^2=0

Wy multiply elements

480c^2+(-42c)+(-310c)=0

We get rid of parentheses

480c^2-42c-310c=0

We add all the numbers together, and all the variables

480c^2-352c=0

a = 480; b = -352; c = 0;
Δ = b2-4ac
Δ = -3522-4·480·0
Δ = 123904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{123904}=352$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-352)-352}{2*480}=\frac{0}{960}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-352)+352}{2*480}=\frac{704}{960}
=11/15
$