9(3n+1)=7(7n+3)+6

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Solution for 9(3n+1)=7(7n+3)+6 equation: 



9(3n+1)=7(7n+3)+6

We move all terms to the left:

9(3n+1)-(7(7n+3)+6)=0

We multiply parentheses

27n-(7(7n+3)+6)+9=0



We calculate terms in parentheses: -(7(7n+3)+6), so:

7(7n+3)+6

We multiply parentheses

49n+21+6

We add all the numbers together, and all the variables

49n+27

Back to the equation:

-(49n+27)



We get rid of parentheses

27n-49n-27+9=0

We add all the numbers together, and all the variables

-22n-18=0

We move all terms containing n to the left, all other terms to the right

-22n=18

n=18/-22

n=-9/11

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