-4(3b+4)+(3b-2)=0

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Solution for -4(3b+4)+(3b-2)=0 equation: 



-4(3b+4)+(3b-2)=0

We multiply parentheses

-12b+(3b-2)-16=0

We get rid of parentheses

-12b+3b-2-16=0

We add all the numbers together, and all the variables

-9b-18=0

We move all terms containing b to the left, all other terms to the right

-9b=18

b=18/-9

b=-2

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