9(2k+3)+2=11(k+192)

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Solution for 9(2k+3)+2=11(k+192) equation: 



9(2k+3)+2=11(k+192)

We move all terms to the left:

9(2k+3)+2-(11(k+192))=0

We multiply parentheses

18k-(11(k+192))+27+2=0



We calculate terms in parentheses: -(11(k+192)), so:

11(k+192)

We multiply parentheses

11k+2112

Back to the equation:

-(11k+2112)



We add all the numbers together, and all the variables

18k-(11k+2112)+29=0

We get rid of parentheses

18k-11k-2112+29=0

We add all the numbers together, and all the variables

7k-2083=0

We move all terms containing k to the left, all other terms to the right

7k=2083

k=2083/7

k=297+4/7

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