(7p+1)(7p-1)=

Solution for (7p+1)(7p-1)= equation:

(7p+1)(7p-1)=

We move all terms to the left:

(7p+1)(7p-1)-()=0

We add all the numbers together, and all the variables

(7p+1)(7p-1)=0

We use the square of the difference formula

49p^2-1=0

a = 49; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·49·(-1)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*49}=\frac{-14}{98}
=-1/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*49}=\frac{14}{98}
=1/7
$