9(2-k)=3(k-9)

Solution for 9(2-k)=3(k-9) equation:

9(2-k)=3(k-9)

We move all terms to the left:

9(2-k)-(3(k-9))=0

We add all the numbers together, and all the variables

9(-1k+2)-(3(k-9))=0

We multiply parentheses

-9k-(3(k-9))+18=0


We calculate terms in parentheses: -(3(k-9)), so:

3(k-9)

We multiply parentheses

3k-27

Back to the equation:

-(3k-27)


We get rid of parentheses

-9k-3k+27+18=0

We add all the numbers together, and all the variables

-12k+45=0

We move all terms containing k to the left, all other terms to the right

-12k=-45

k=-45/-12

k=3+3/4