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2/3n+1=3/5n
We move all terms to the left:
2/3n+1-(3/5n)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 5n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
2/3n-(+3/5n)+1=0
We get rid of parentheses
2/3n-3/5n+1=0
We calculate fractions
10n/15n^2+(-9n)/15n^2+1=0
We multiply all the terms by the denominator
10n+(-9n)+1*15n^2=0
Wy multiply elements
15n^2+10n+(-9n)=0
We get rid of parentheses
15n^2+10n-9n=0
We add all the numbers together, and all the variables
15n^2+n=0
a = 15; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·15·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*15}=\frac{-2}{30} =-1/15 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*15}=\frac{0}{30} =0 $
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