9(2-3x)-29=8x-(x+3)

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Solution for 9(2-3x)-29=8x-(x+3) equation: 



9(2-3x)-29=8x-(x+3)

We move all terms to the left:

9(2-3x)-29-(8x-(x+3))=0

We add all the numbers together, and all the variables

9(-3x+2)-(8x-(x+3))-29=0

We multiply parentheses

-27x-(8x-(x+3))+18-29=0



We calculate terms in parentheses: -(8x-(x+3)), so:

8x-(x+3)

We get rid of parentheses

8x-x-3

We add all the numbers together, and all the variables

7x-3

Back to the equation:

-(7x-3)



We add all the numbers together, and all the variables

-27x-(7x-3)-11=0

We get rid of parentheses

-27x-7x+3-11=0

We add all the numbers together, and all the variables

-34x-8=0

We move all terms containing x to the left, all other terms to the right

-34x=8

x=8/-34

x=-4/17

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