3z+16=2(-z+33)

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Solution for 3z+16=2(-z+33) equation: 



3z+16=2(-z+33)

We move all terms to the left:

3z+16-(2(-z+33))=0

We add all the numbers together, and all the variables

3z-(2(-1z+33))+16=0



We calculate terms in parentheses: -(2(-1z+33)), so:

2(-1z+33)

We multiply parentheses

-2z+66

Back to the equation:

-(-2z+66)



We get rid of parentheses

3z+2z-66+16=0

We add all the numbers together, and all the variables

5z-50=0

We move all terms containing z to the left, all other terms to the right

5z=50

z=50/5

z=10

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