9(2-3x)-29=4(x-5)

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Solution for 9(2-3x)-29=4(x-5) equation: 



9(2-3x)-29=4(x-5)

We move all terms to the left:

9(2-3x)-29-(4(x-5))=0

We add all the numbers together, and all the variables

9(-3x+2)-(4(x-5))-29=0

We multiply parentheses

-27x-(4(x-5))+18-29=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

-27x-(4x-20)-11=0

We get rid of parentheses

-27x-4x+20-11=0

We add all the numbers together, and all the variables

-31x+9=0

We move all terms containing x to the left, all other terms to the right

-31x=-9

x=-9/-31

x=9/31

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