7x+4x-80=40-9x

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Solution for 7x+4x-80=40-9x equation: 



7x+4x-80=40-9x

We move all terms to the left:

7x+4x-80-(40-9x)=0

We add all the numbers together, and all the variables

7x+4x-(-9x+40)-80=0

We add all the numbers together, and all the variables

11x-(-9x+40)-80=0

We get rid of parentheses

11x+9x-40-80=0

We add all the numbers together, and all the variables

20x-120=0

We move all terms containing x to the left, all other terms to the right

20x=120

x=120/20

x=6

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