3b+12=3(1b-6)+4

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Solution for 3b+12=3(1b-6)+4 equation: 



3b+12=3(1b-6)+4

We move all terms to the left:

3b+12-(3(1b-6)+4)=0

We add all the numbers together, and all the variables

3b-(3(b-6)+4)+12=0



We calculate terms in parentheses: -(3(b-6)+4), so:

3(b-6)+4

We multiply parentheses

3b-18+4

We add all the numbers together, and all the variables

3b-14

Back to the equation:

-(3b-14)



We get rid of parentheses

3b-3b+14+12=0

We add all the numbers together, and all the variables

26!=0

There is no solution for this equation

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