# 9^2+b^2=14^2

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## Solution for 9^2+b^2=14^2 equation:

9^2+b^2=14^2
We move all terms to the left:
9^2+b^2-(14^2)=0
We add all the numbers together, and all the variables
b^2-115=0
a = 1; b = 0; c = -115;Δ = b2-4acΔ = 02-4·1·(-115)Δ = 460The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{115}}{2*1}=\frac{0-2\sqrt{115}}{2} =-\frac{2\sqrt{115}}{2} =-\sqrt{115}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{115}}{2*1}=\frac{0+2\sqrt{115}}{2} =\frac{2\sqrt{115}}{2} =\sqrt{115}$

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