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9^2+b^2=14^2

We move all terms to the left:

9^2+b^2-(14^2)=0

We add all the numbers together, and all the variables

b^2-115=0

a = 1; b = 0; c = -115;

Δ = b^{2}-4ac

Δ = 0^{2}-4·1·(-115)

Δ = 460

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{115}}{2*1}=\frac{0-2\sqrt{115}}{2} =-\frac{2\sqrt{115}}{2} =-\sqrt{115} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{115}}{2*1}=\frac{0+2\sqrt{115}}{2} =\frac{2\sqrt{115}}{2} =\sqrt{115} $

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