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(7/3)t=84

We move all terms to the left:

(7/3)t-(84)=0

Domain of the equation: 3)t!=0We add all the numbers together, and all the variables

t!=0/1

t!=0

t∈R

(+7/3)t-84=0

We multiply parentheses

7t^2-84=0

a = 7; b = 0; c = -84;

Δ = b^{2}-4ac

Δ = 0^{2}-4·7·(-84)

Δ = 2352

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{3}}{2*7}=\frac{0-28\sqrt{3}}{14} =-\frac{28\sqrt{3}}{14} =-2\sqrt{3} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{3}}{2*7}=\frac{0+28\sqrt{3}}{14} =\frac{28\sqrt{3}}{14} =2\sqrt{3} $

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