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8z^2+15z-27=0
a = 8; b = 15; c = -27;
Δ = b2-4ac
Δ = 152-4·8·(-27)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-33}{2*8}=\frac{-48}{16} =-3 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+33}{2*8}=\frac{18}{16} =1+1/8 $
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